Chemistry numerical.... ? Answers:1 | LastAnswerAt:2011.04
Question 
- Μađħaνi
- Asked at 2011.04.20 23:18:26
3 moles of a mixture of FeSO4 and Fe2 ( SO4)3 required 100 ml. of 2 molar (M) KMnO4 solution in acidic medium. hence mole fraction of FeSO4 in the mixture is - ?
> 1/3
>2/3
>2/5
>3/5
ALSO EXPLAIN THE PROCEDURE IF U GET THE ANS.
Answer- 1/3 ( i want the explaination for this ans. pls )
answer Steve O Answered at 2011.04.20 23:18:26
find moles of standard:
0.100L of 2 mol / Litre = 0.200 moles of KMnO4
by the reaction:
1 KMnO4 (5 e- each)& 5 FeSO4 (1 e- each) -->1 Mn+2 & 5 Fe+3
0.200 moles KMnO4 @ 5 mol FeSO4 / 1 mol KMnO4 = 1.0 mol FeSO4
1 mol FeSO4 / 3 mol total =
your answer: 1/3
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